Well, that means its 3^9 = 19,683 tries.. shouldnt be too hard; I could do this in autoit and have it manually but .. does anyone have an idea on how to use python for this?
I guess there are 3 spots and 10 numbers to be used I.e from 0 to 9. That makes it 10^3=1000 combinations .
Am I getting it right that the password is 3 characters long and can use numbers from 0-9 ?
If yes. Then I can do this job for you, can make a C program and force feed the passwords in the file.
What if the file doesn't open even after all the possible combinations? Do I still get the bounty?