Im not great with odds but can anyone tell me the odds of getting 3 seperate transaction rolls over 64 000 in a row? I know that its about 2.5% to get 1 roll over 64000.
Yes, I can. You probably mean 64000 or over, since 64000 is a losing roll when you're playing "lessthan 64000" too.
The probability of losing a single "lessthan 64000" is:
>>> 1 - 64000/65536.0
0.0234375
Or about a 1-in-42.666 shot.
To find the probability of it happening 3 times in a row, you just cube that number:
>>> (1 - 64000/65536.0)**3
1.2874603271484375e-05
That's scientific notation for 0.00001287, and represents a 1-in-77672 shot.
In other words, it's pretty unlikely and probably has never happened since "lessthan 64000" has been played less than 9000 times.
It may have happened of course - it wouldn't be incredibly unlikely. Not like losing 60 "lessthan 32000" bets in a row, which is so unlikely it will almost certainly never happen.
Edit: note that you'll need to multiply probabilities by 100 to get percentages. And note also that 42.666 cubed is 77672.
Edit 2: I notice you didn't specify that you were playing "lessthan 64000" at the time. It's much more likely that someone has got three rolls over 64000 in a row when they were playing other bets. It's just that "lessthan 64000" is a relatively unpopular bet, and wasn't even available for probably half of SatoshiDice's lifetime so far.