On-thread Trivia!
aaaand the question for today is:
Q. You are to divide 9 balls - 4 green and 5 red into 2 boxes. You pick a box at random and a ball from it at random. If it is red, you DIEEEE!, if it is green (I will let) you live. How would you maximize your odds of living?
aaaand the question for today is:
Q. You are to divide 9 balls - 4 green and 5 red into 2 boxes. You pick a box at random and a ball from it at random. If it is red, you DIEEEE!, if it is green (I will let) you live. How would you maximize your odds of living?
If I can put the ball by myself, I will put 5 red + 3 green in the first box and left the 1 green ball in the second box. So whenever I pick the box, I know that the box with just 1 ball on it is have the green ball.
And if I'm not allowed to put the ball by myself, I will just pick the box with less balls. Because the box with more balls is has to be the red ball in it