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I think that what you have done is to pretty much prove it is random and there is no predictive formula.
I'm not sure.
I got some infos that are getting me to believe that there is a possible formula behind it.
I give you an example. I'm playing around by creating random formulas, and I get pretty much similar results. Yet they are predictable with a formula.
All I use for inputs are 2 arrays, one with the current position and another with the sequential list of prime numbers.
For example:
Consider n = count, p = prime numbers, and y = sequence based on the formula 2^n + (n mod p) * Log(n+1, 2) <--- Random formula I invented.
y / 2^p + 1 and y-2^p *-1 are similar formulas to what was shown before for the var x in the real sequence, their results also appear to be random...
n | p | y = 2^n + (n mod p) * Log(n+1, 2) | y / 2^p + 1 | y-2^p *-1
|
0 | 2 | 1 | 1.25000000 | 3
|
1 | 3 | 3 | 1.37500000 | 5
|
2 | 5 | 7 | 1.22406016 | 25
|
3 | 7 | 14 | 1.10937500 | 114
|
4 | 11 | 25 | 1.01234752 | 2023
|
5 | 13 | 45 | 1.00548399 | 8147
|
6 | 17 | 81 | 1.00061679 | 130991
|
Yet this sequence is breakable with a simple formula.
EDIT: this formula doesn't make any sense I know, just playing around
