Post
Topic
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
bdb
on 07/01/2016, 23:57:49 UTC
I have the formula:
    y = 2n-1 + [rand() MOD (2n-1)]

[edit] or rather:
    y = 2n-1 + [rand() MOD 2n-1]