Okay now we are starting to get some evidence that there might be a coordinated attack to hide the facts I have presented (note the following thread move to Meta is not the thread that Gmaxwell deleted)
People have refuted your theory but you just don't want to listen.
"If you sign the same message with the same key, you will get a different signature".
Your chances to get the same signature is ~1/2^256. Why? Because of the the 3rd step of the ECDSA algorithm. Quoting from
https://en.wikipedia.org/wiki/Elliptic_Curve_Digital_Signature_AlgorithmCalculate e = \textrm{HASH}(m), where HASH is a cryptographic hash function, such as SHA-2.
Let z be the L_n leftmost bits of e, where L_n is the bit length of the group order n.
Select a
cryptographically secure random integer k from [1, n-1].
Calculate the curve point (x_1, y_1) = k \times G.
Calculate r = x_1\,\bmod\,n. If r = 0, go back to step 3.
Calculate s = k^{-1}(z + r d_A)\,\bmod\,n. If s = 0, go back to step 3.
The signature is the pair (r, s).
Their emphasis, not mine.
Now, tell me. How did CW come up with the same signature as something from the blockchain if he was casually signing a message? Bear in mind that k is chosen by the signing software (openssl) and not an input from the user.