all,
* Each Aztec pixel has a triangle and an orange dot. There are 26 unique combinations of dots + triangles (9*3 - 1 combo which never used), which seems to imply a basic alphabetical substitution cipher.
Guess what? The keypad in the cell is a QWERTY Keyboard. A QWERTY Keyboard has exactly 26 letter keys, only letters not including numbers nor special characters or other keys. Counting just the letters.
Can that lead somewhere? "The journey inward begins here", so if G (in the middle of the keyboard) is the middle square can the other letters be mapped easily?
Or maybe decide where to start from with the squares and replacing the first 6 with QWERTY (1 per square) in a spiral way as mirth23 mentioned?
6b 7a 8b 7a 2b 2b 1d 6a 9b
8a 1d 1d 3d 7a 1a 1d 2a 3b 1a 6d 5a
_8a_ 6b 1a _7d_5d 5b 4a 7b 2d
9b 2d _8d_3b 5a 3d 8b 2d
6a 7b 9a 8d 7b 7b 8d 4d
4d 6b 3d 2b 7b 2b 2b 7b 2a 9b 5b 4d 8d 1b 4b
1b 8a 2a 4b 2a 1b 8b
6d 3d 6b 9a 4a 8b 3d 7d 8a
1a 9a 4a 6d 7d 1a 5a
3a 6a[2b] 7d 4a 7d 6b 3d 3b 7a _4d_
3d 3d 9b 4b 3b 4b 1b
9a 5a 9a 5a 3a 6a 4b _7a_ 9b
3b 1a 9b 2b 8a 8d 6b
8a 2a 6a 8a 1b 1b 8a 7a 1a 7a 3b 9a 7a 6b 4d
7d 9b 5b 2b 6b 6d 1b 1b 1b
#b 3b 1b 6b 3b 3a 3b 7d
1b 6a 3a 8b 5b 9a 7a 2a 8d
2d 6b *a 6d 5d 5d 1a 1b 7a 5b 6d 7b 5d
7b 2d 3d 8d 3d 9b 7d 8b 6a
# = 6 (or 2 or 3)
* = 2 (or 1 or 4)
[2b] = might be 3b
Unfortunately I don't know how the mapping works... But I'm sure others here can have a go.