It would definitely be bullet #2 that hit the glass first... followed by bullet #3 and last was bullet #1. The reasoning being that #2 doesn't have any cracks that are "stopped" by existing cracks, #3 only has a crack stopped by cracks from #2, and #1 has cracks that are stopped by both #2 and #3.
That was a pretty easy one compared to the maths involved with the probabilities of dying in games of Russian roulette

Hi there!
Here is the challenge to test you knowledge of physics. Imagine you are climbing mountain and see as the plane passes near by. Meanwhile in plane two guys decide to play russian roulette and one of them triggers pistol to shoot the bullet in the opposite direction to the plane's movement trajectory. The initial bullet's speed is equal to the plane's speed.
QUESTION:What will happen to the bullet in climber's point of view? Would it stay with climber or fly in any direction?