Re: BYTEBALL: Totally new consensus algorithm + private untraceable payments
CryptKeeper, I sent 111 bytes to the first address and 999 bytes to the second, did you receive them? Both transactions cost 589 bytes, does this mean that the fee is set to this amount whatever the number of bytes one sends?
Yes, I acknowledge!
I cannot see who has sent these tx, there is no sender address! Is this meant to be like this?
I've seen the 589 Bytes fee also for my own tx. IMHO this tx type "send bytes" has a size of 589 bytes, so we have to pay 589 Bytes!
Other tx types may vary in fees because of a different tx size.