nLastPOWBlock = 31000;
nLastFairLaunchBlock = 1001;
{
int64_t nSubsidy = 0;
if (nHeight <= 0)
nSubsidy = 0;
else
if (nHeight <= nLastFairLaunchBlock)
nSubsidy = 1000000 * COIN;
else
if (nHeight <= 31000)
nSubsidy = 10 * COIN;
else
if (nHeight <= nLastPOWBlock)
nSubsidy = (NetworkID() == CChainParams::TESTNET ? 10000 : 400) * COIN;
}
coins created by miners at the end of POW (if there wasn't POS blocks) - 299990
coins owned by the dev - 650 000 000
let's math what will be the percent of coins which will be fairly distributed between the miners (if there is no POS during the POW)
299990/650000000*100 = 0.0461523077%
for the dev left
100%-0.0461523077%=99.9538477% of the total supply (and this is if the POS wasn't start)
as you see in the code the last 'if' is unreachable
