Re: Why Bitcoin Core Developers won't compromise

(*) it is obvious because bitcoin is not a good unit of account, there's no mechanism in it that adapts the emission of bitcoin with its value with the aim to stabilize it, and bitcoiners are even proud of that. Something that is not a good unit of account (volatile value) cannot be generally used as a currency in a payment system.

Bitcoin has perfect stability - it has always maintained a value of 1BTC = 1BTC.

Oh, you meant its price in USD? Why would that be relevant to its stability? You are using a very unstable currency (USD) as a measuring stick. Any currency that replaces fiat must be volatile, because it has a lot of growing to get to that point, and its not going to chart a straight line on the way.

No, I mean in Big Mac of course. How many Big Macs could you buy with 1 BTC in November last year ? And how many big macs can you buy now with 1 BTC ?

How many Big Macs could you buy with $1000, in November ? And right now ?

Big Macs are priced in dollars. See the difference? One is the established currency, and one is replacing an established currency. The replacer inherently CAN'T have the same pricing stability as the currency it is replacing. The former has to rise against the latter which includes against items priced in the latter.

Trying to peg a new currency to an established one is a fool's dream because it goes against non-fiat monetary fundamentals. A currency needs to grow in value organically ie. go up in price as it is adopted so that price is an indicator. Trying to rig that is no better than a fiat scheme.