Re: FreeBitco.in - Win free Bitcoins every hour!

I did some maths... and if the number is really fair, the average roll will give 2-3 cents... (If you would roll 100,000 times, it would probably be 2-3 cents average). How is this profitable for you? 2 cents would mean you have to get $20 per thousand visits to have enough money to pay your users... But how does that work? Really... I'm curious... Is it simply because most users lose it all in the Multiply BTC or is it some dark secret you don't want us to know?

How did you arrive at 2-3 cents for the average roll? The top Free BTC roll prize is $200, it's fixed along with all prize levels below it, regardless of the price of bitcoin.

Lmao... I understand that it's all fixed. That's how I arrived at 2-3 cents (I did it in my head and my head isn't that exact Tongue

) the exact value is: $0.027137, so basically 2.7 cents.

I can show you my calculation if you want..

https://docs.google.com/document/d/1JtwnXVjswztX0gVzqffW0gaKppQyWGG_dl4Kcnt6HDg/edit?usp=sharing

That's the document I put clear calculations in.

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If there are 6 available prizes, being the maximum 200$ 0.1$ st the moment, and each prize is divided by 10, the you have 0.1/0.01/0.001/0.0001/0.00001/0.000001 then, it would be 200$/20$/2$/0.2$/0.02$/0.002$, and that 0.002$ is the average roll on every user

I don't get what you're trying to say... 0.002$ is the average roll on every user? That's nonsense. $0.002 is like the base roll and because there is a chance on the higher prizes, it adds to that base roll. On average, you will hit the $200 every 10,000 rolls, so you basically get $0.02 (2 cents) every roll you play. It's simple maths bro. If you roll 1 million times, I'm pretty sure you would get ~27k worth of moneys