The author, there is no need to go to the 256-bit address. 160 bits is enough to ensure the security of the address.

The problem is completely contrived.

In order to get a collision with a probability of 1.77636E-15 (and this probability is negligible, there is a higher chance of winning the lottery) there must be a blockchain in which 2 ^ 56 addresses will be used, each address being 20 bytes (160 bit). In total, the blockchain with such an amount of addresses will occupy not less than 2 ^ 56 * 20 = 1441151 TB (this is the lowest estimate), by the way, at the moment, the blockchain is only 126 GB.