Ughh, fuck, I was wrong
9999 combinations x 9999
You're right
Sorry
Wow, that is hard to hit!
Even if it was 1 : million it would need to be over 160
BTC to be profitable
So this way it would need to be 16 000
BTC 
Hmm, that doesn't sound right.
My back of the envelope calculations is anything >1000
BTC. Each bet you have 1 in 10 million chance of winning the jackpot. To qualify for the jackpot you have to "spend" 0.0001 BTC in EV. So I think you can model it as approximately:
(1 / 1e7) * jackpot - 0.0001 = 0 which gives you
jackpot = 1000 to be 0EV, and thus everything above that "profitable"
If you make a 100 million bets, you only have a 64% chance of winning the jackpot
With a 1% loss on each rollover
1000
BTC = 10 million 0.0001 bets
You need to make 10 rollovers in order to hit 100 million bets
Which should be a 10% loss according to the house edge, a loss of a 100
BTC0.0001
BTC bets yield 1% of the jackpot
Which would be 10
BTCSo a 1000
BTC jackpot would yield 10
BTCSo, basically with a 1000
BTC jackpot, you'd lose 100
BTC for a 64% chance to win 10
BTCDoesn't seem very positive EV to me
If chances of you losing the bet are 9999:1 (99.9%), then losing it twice in a row would be 0.999x0.999= 99.8%, losing it three times in a row 0.998x0.999= 99.7% etc. up until you get to a hundred million bets and a 36% chance of losing that bet
Therefore, a 1000
BTC jackpot gives you a chance to win 10
BTC while losing 100
BTC to the edge at a 64% chance
Right?