Anybody have an answer to my last question on double hashing?
Hello
2cf24dba5fb0a30e26e83b2ac5b9e29e1b161e5c1fa7425e73043362938b9824 (first round on sha-256)
d7914fe546b684688bb95f4f888a92dfc680603a75f23eb823658031fff766d9 (2nd round of sha-256, from hashing the above value)
However the wiki page above says the 2nd round should yield this value:
9595c9df90075148eb06860365df33584b75bff782a510c6cd4883a419833d50
What am I doing wrong?
Usually when someone asks this question it is because they are hashing the result of the first hash as a string of characters rather than as a block of binary data.
(ex. 0A would be a hex representation of 00001010, but as a string it would be represented as 00110000 01000001)