The efficiency of your fee is not dependent on the actual amount of coins, but on how much they are in proportion to the size of your transaction, expressed in satoshi per byte (sat/byte).
So in your case: 175028/input size = fee in sat/byte
Assuming you only have 1 input (we can't know for sure, but you should be able to preview your tx in your wallet to see) with an average of 250 bytes, your fee would be just above 700 sats/byte. That would get you confirmed fairly quickly right now (within 2 blocks estimation)
Check it against https://bitcoinfees.earn.com/ for an estimation of how long that would take to confirm.
So in your case: 175028/input size = fee in sat/byte
Assuming you only have 1 input (we can't know for sure, but you should be able to preview your tx in your wallet to see) with an average of 250 bytes, your fee would be just above 700 sats/byte. That would get you confirmed fairly quickly right now (within 2 blocks estimation)
Check it against https://bitcoinfees.earn.com/ for an estimation of how long that would take to confirm.
Thanks a lot buwa
I have got 4 inputs (4 different times I bought btc) and now want to move from exchange to wallet.
So it would be 175028/(250*4)=175.028 sats/byte?
Cheers!