I obviously don't want to pay the $1000 fee. And yes, I understand the smaller transactions will cost a bit more. That's why I'd like to understand how this "Minimum .1 BTC fee" works. What is the cutoff, how can it be changed/worked around.

And I was hoping to do it without rawtransactions, which I am familiar with but don't feel comfortable using.

Can someone explain the ".1 BTC Minimum fee" and the exact mechanics - surely it's in the code somewhere. And yes I'd call it a bug that it overrides user set fee without warning from the normal command line send.

Thanks for the responses.

Sending

Users can decide to pay a predefined fee rate by setting `-paytxfee=` (or `settxfee ` rpc during runtime). A value of `n=0` signals Bitcoin Core to use floating fees. By default, Bitcoin Core will use floating fees.

Based on past transaction data, floating fees approximate the fees required to get into the `m`th block from now. This is configurable with `-txconfirmtarget=` (default: `2`).

Sometimes, it is not possible to give good estimates, or an estimate at all. Therefore, a fallback value can be set with `-fallbackfee=` (default: `0.0002` BTC/kB).

At all times, Bitcoin Core will cap fees at `-maxtxfee=` (default: 0.10) BTC. Furthermore, Bitcoin Core will never create transactions smaller than the current minimum relay fee. Finally, a user can set the minimum fee rate for all transactions with `-mintxfee=`, which defaults to 1000 satoshis per kB.


Note that a typical transaction is 500 bytes.