Guys I would like to apologize for a mistake I made in my previews analysis.
I assumed that the private WIF key is random (private/public key pair was generated with a vanitygen like tool without modifications)
so my conclusion was that the "yellow/red", "green/blue" bit stream can not encode a private key.
Unfortunately my assumption might not nesesery be true,
in fact there only needs to be about length("FLAMEN6")*6bits= 7*6bits = 42bits random bits in a stream to generate a public key with "1FLAMEN6" prefix,
so not only the "yellow/red", "green/blue" stream may contain a valid private key, but also only the "short/long" stream is enough to create a valid private key with a "1FLAMEN6" prefix.
Even more, it's probably possible to modify the original vanitygen source code so, that the time it would take to find such a private key is the same as now (on my laptop the estimation is ~5 days). The only change would be to feed vanitygen not with random numbers but with a desired bit pattern + the 42 random bits.
If this is the case in this puzzle, you have to decide for yourself.
I don't see a reason to apologize. We all have ideas that might lead to something or not. Thanks for your correction.
With oclvanitygen I only get ~8 hours estimation for 1FLAMEN6. The creators are into cryptocurrency for many years already so they will have tools and processing power to create keys how they desire in a fraction of time.