2 out of 3 outputs are yours: 3Lzs3s6p (0.131 BTC) and 1MoTG1qn (0.008 BTC)
but the 3rd isn't? however you've received 0.011951 BTC back to your address 3Lzs3s6p
so the thief sent you back 0.011951 BTC and only stole 0.0480377 BTC
this just doesn't make sense, and why wouldn't he just steal all of them at the first chance he got?
how exactly you created the multisig address in the first place? in 2015
why 3-of-3 multi-sig? do you hold all the private keys?
and how did you compose/sign the transaction before broadcasting it?
edit: just noticed... both BTC and BCH transactions used the same tx fee of
0.0009