If you count all Coca Colas, that have to be cooled down to 5 C at this moment, you will find out that it uses 10 times more energy than Bitcoin mining.
Wow, somebody went and created a Reddit topic about it:
https://www.reddit.com/r/Bitcoin/comments/9vsoft/how_much_energy_does_it_take_to_cool_down_all/Posted byu/zzanzare
3 days ago
Anyhow seems you were a bit wrong, a few hundred times wrong:
I disagree by more than 2 orders of magnitude with your calculation but the conclusion is about the same:
35 30 -> 5 degrees: 25 degrees
8 oz = 226 gram
1.7 Billion servings / day
Specific heat of water: 4.2 Joule/gram/degree (a well known number)
Heat per serving = 25 x 226 x 4.2 = 23730 Joule
Total heat = 23730 x 1700000000 = 40341000000000 Joule/day
1 kWh = 3600000 joule
Total heat = 40341000000000 / 3600000 = 11205833 kWh/day
1 TWh = 1000000000 kWh
Total heat = 11205833/1000000000 = 0.01120 TWh/day
Taking the COP of 2 into account, energy required is half (thanks user Watada) that.
Total heat consumption = 0.00560 TWh/day