Post
Topic
Board Gambling discussion
Re: Make money with martingale applied to dice game ?
by
o_e_l_e_o
on 16/11/2018, 17:17:00 UTC
Hello, I know martingale  is useless for long term for dice game  but   if you have a big bank and can support  1 serie of 20 loose, you will always win no ,?
The world record  for the roulette is one serie of  26 red , it will never happen again,the odd are just very low 
So if we   do martingale  with a bank that can support  20-25 loose, we will definitly make money

Nope.

First of all, there is absolutely no guarantee that you will only lose 25 times in a row. It doesn't matter if you have lost 2 or 25 in a row - with a house edge of 1% on most crypto dice games, you have exactly a 50.5% change of losing again. Assuming otherwise is known as the Gambler's fallacy. The world record is actually a series of 26 black in a row, and millions were lost during this streak as gamblers wrongly assumed (as you have done) that red was more likely to come up next.

Secondly, assuming an initial bet of only $1 (and therefore, a profit on every run of only $1), the bankroll needed to support a losing streak of 25 is $33,554,432. If you are willing to risk $33.5 million to potentially win $1, then I have a bridge to sell you.