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Scam Accusations
Re: Freebitco.in provably cheating
by
coinlocket$
on
09/01/2019, 21:29:02 UTC
Quote from: broke_tradah on January 09, 2019, 09:23:04 PM
Quote from: coinlocket$ on January 09, 2019, 09:18:02 PM
99,9999173% 20000 <----
This is still only for 1 number.
No, is for a range of 7 numbers and the math is:
(1-((1-7/10000)^20000))x100=99,9999173%
For 1 number is
(1-((1-1/10000)^20000))x100=86,4678251%