Does anyone have any idea how often let's say 15-20 red streak come and go? Would like people who have somewhat of an idea, thanks!
You can calculate the odds quite easily. Simply raise the odds of each red happening to the power of the amount of times that you want to account for.
However, one of the more common fallacies in this area is the fact that rolls are not dependent on each other. A lot of people do prerolls and all that in the hopes that they can somehow increase their odds of winning, but what they don't realize is that prerolls don't matter at all because each roll is independent of the other.
That's why I think it's a bit redundant to ask this question to somehow come up with a strategy. Prerolling 19 times doesn't increase the chances of your 20th roll hitting.
Please correct me if I'm wrong. In terms of computing probability you will have to take into consideration the number of times that you will roll, which means that individual rolls, although seemingly independent from each other, are actually somehow connected. Although pre-rolling is a myth to me, the rule of probability will tell you that after rolling 19 times in a row and you got red in all of them, that 20th roll has a very high probability of giving you a green. Even if that next roll has 50% chance of winning, since we take into consideration the 19 consecutive reds in the previous rolls, the probability for a green is high.
Every outcome on bustabit is a series of 10 million pre-generated numbers whose median is 1.98.
So, there could be any number of reds or greens as it's totally random. AFAIK, hypothetically, there could be thousands of reds without a green.
But the largest numbers of red we've seen is around 20 or something till date.