Here is what I understand from reading the fairness section.

Calculating first dice result:

First four bytes: 2202b355

First byte: 22
Second byte: 02
Third byte: b3
Forth byte: 55

Hexadecimal must be converted to decimal:
22 --->  34   (a)
02 --->  2     (b)
b3 --->  179   (c)
55 --->  85   (d)

Now you should use the following formula to obtain a value between zero and one

(a/256)+(b/256²)+(c/256³)+(d/256⁴)

(34/256)+(2/256²)+(179/256³)+(85/256⁴) = 0.13

0.13 must be multiplied by 6

0.13*6 = 0.78

The final dice result is

[0.78]+1 = 1

Calculating second dice result:

Second four bytes: 351a1b6b

First byte: 35
Second byte: 1a
Third byte: 1b
Forth byte: 6b

Hexadecimal must be converted to decimal:
35 --->  53  
1a --->  26    
1b --->  27  
6b --->  107


(53/256)+(26/256²)+(27/256³)+(107/256⁴) = 0.207

0.207 must be multiplied by 6

0.207*6 = 1.25

The final dice result is

[1.25]+1 = 2