Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

Quote from: arulbero on February 15, 2020, 11:22:39 PM

Quote from: bytcoin on February 15, 2020, 11:17:49 PM

I'm not good at math ... But I don't think it's that easy! Can you create a tool that I can test? If you really did it ... I'll send you 3 BTC

If you use python:

copy this file "test.py"

Code:

#!/usr/bin/env python

p = 115792089237316195423570985008687907852837564279074904382605163141518161494337
a = 76470300715912249562689990107401687364194232406198996658976353330269918489458
b = 64658408237276871767689061520961436408509493287485285377611016482361694763299

b_inv = pow(b, p-2, p)
w1 = a*b_inv % p
print (w1)

a_inv = pow(a, p-2, p)
w2 = b*a_inv % p
print (w2)

and then in the terminal:

python test.py

Code:

$ python test.py
12447032699845648078645791161909514142990644957498005805208944683777961822095
66620152837833785920928131416087065201280002472666144035333386572317622196480

One question ... how did you discover the value of a and b?

Discover this!

p = 115792089237316195423570985008687907852837564279074904382605163141518161494337
a = Huh

??
b =

??

w = GF(p)

w (((a / b)))
w (((b / a)))

w= 41689968412277401815192940146121615515073176981576112778517871276338175969527
w= 94599322545067982882578206403521588574602656593708975301033069273870448067861

I will send you 1 BTC if you find the value a and b