Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Sorry for the post off topic ... but can someone develop a tool to solve this?
p = 115792089237316195423570985008687907852837564279074904382605163141518161494337
a =
?
b =?
w = GF(p)
w (((a / b)))
w (((b / a)))
w= 12447032699845648078645791161909514142990644957498005805208944683777961822095
w= 66620152837833785920928131416087065201280002472666144035333386572317622196480
If you can develop any tool that does this ... I will send you 3 BTC
p = 115792089237316195423570985008687907852837564279074904382605163141518161494337
a =
?b =
?w = GF(p)
w (((a / b)))
w (((b / a)))
w= 12447032699845648078645791161909514142990644957498005805208944683777961822095
w= 66620152837833785920928131416087065201280002472666144035333386572317622196480
If you can develop any tool that does this ... I will send you 3 BTC
Well, that's easy:
Code:
0 < b < p
a = b * 12447032699845648078645791161909514142990644957498005805208944683777961822095 (mod p)
So, an obvious solution is a=12447032699845648078645791161909514142990644957498005805208944683777961822095, b=1a = b * 12447032699845648078645791161909514142990644957498005805208944683777961822095 (mod p)
The correct is:
a = 76470300715912249562689990107401687364194232406198996658976353330269918489458
b = 64658408237276871767689061520961436408509493287485285377611016482361694763299
I need a tool that finds the a and b value correctly
The values I provided for a and b are correct, given the input. According to the puzzle there are a bit less than 2256 possible pairs.
The screenshot provides more information, one could see the tops of the numbers, and restrict a and b. A quick look makes it obvious where 7 5 4 1 6 are.