I'm not at all sure if it will work with a wider range (say for instance 000000000000000000000000000000000000000000000001A838B13505B26867:0000000000000000000000000000000000000000000000349B84B6431A6C4EF1 which is 65 and 70). Might be able to test this using some of the already solved values (like plug in L of 48 and U of 53 and look for 51's key). If I'm wrong and this is silly, please let me know, sir Alek. I'm by no means a math or programming guy, just a tinkerer.