-snip-
PS. Actually instead of solving pk110 within the range [2^109 ... 2^110-1] the program solves the key pk110s within the range [0 ... 2^109-1]
Thanks for the detailed answer. This is very clear now.PS. Actually instead of solving pk110 within the range [2^109 ... 2^110-1] the program solves the key pk110s within the range [0 ... 2^109-1]
So the tames work from range 0...meaning 0x0 to 0x3FFFFFFFFFFFFFFFFFFFFFFFFFFFF (for pubkey 110)?
The range is shifted, not expanded. Shift means the move of start and end values both by the SAME value.
Instead of range [2000000000000000000000000000 ... 3fffffffffffffffffffffffffff] the program works with range [0 ... 1fffffffffffffffffffffffffff]
PS. Do you really like these hex values posted here? They are difficult to understand by a human (as difficult to count "f" and "0" signs). So i represented them earlier by the powers of 2 (2^109 and 2^110) which is much easier to understand.