Post
Topic
Board Development & Technical Discussion
Re: Pollard's kangaroo ECDLP solver
by
BitCrack
on 02/06/2020, 12:32:46 UTC
https://cdn.discordapp.com/attachments/511921983655641109/717044247831773184/Unbenannt.PNG

what does all these values mean ?

what is important here the Dp counter all other counters show 2^-inf


btw is someone open to share some workfiles for merge together ?

DP count is most important. You are running at DP 25, so it will take 2^57 (whatever expected group ops is for 115) - 2^25 (your DP setting) so roughly you want your DP count up to 2^32 to be getting close to solving.

I have files for DP 30.  So I need to get close to 2^27 to be getting close to solving. 2^57(expected ops) - 2^30(my DP setting) = 2^27 DP count .



The number of points represented by the DPs is most important. If you are using a 30-bit distinguisher on GPUs, it is going to take way more than 2^27 DP's to solve #115.
You think so? I was using the math that was explained to me...I'm not an expert like some here, but I've seen it been said that way several times.
How long say you, or better yet, how many DPs do I need? 2^what?

That 2^27 figure assumes the average walk length is 2^30. The GPU works by doing many slow walks in parallel e.g. 60 million walks that do 20 iterations per second. At that rate, it will take 2^30 / 20 seconds = 1.7 years before any of the walks are 2^30. Your DP count is going to be a few powers of 2 higher than 27.