Re: Pollard's kangaroo ECDLP solver

Quote from: arulbero on Today at 10:19:51 AM

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You can (see here -> https://bitcointalk.org/index.php?topic=5244940.msg54546770#msg54546770, it is enough to map the new task [1, 2^119 - 1] to the previous one [1, 2^114 - 1]) but it's not worth it.
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i think all DPs from previous work will be in the left 1/32 part of interval(in the begining).
If you just multiply DPs by 32 then they will be just points not DPs becouse they will not have leading zeros.
If i wrong can you explaine in very small range how transform DP by 32 times and do not loose leading zeros? Thanks.