You have computed about 2^58.36 steps. And you know now the private keys of 2^33.36 DPs in the [1, 2^114 - 1] interval (why you said [2^114,2^115-1]? you know only one public key P in [2^114, 2^115 - 1] range, all the public keys/points you have computed lie in [1, 2^114 - 1])
Yes you're right.
I ve forgotten that the start range was shifted to zero. shame on me
It will help to solve #120.
Instead of 2^61 steps, you need to compute (2^60 - 2^58.38) steps for tame + 2^60 for wild.
You could save about 19% of the work.
It would be convenient start with only wild (for the first 2^58.38 steps) and then continue with wild and tame, but with many machine it should be not simple to do this.