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Development & Technical Discussion
Re: How to convert High-S value to Low-S value?
by
AdolfinWolf
on
06/08/2020, 16:15:54 UTC
It seems like the most-used solution is to check if s > N/2, and if so, divide s by N-s (?)
This library seems to support it?
https://github.com/warner/python-ecdsa/search?q=sigencode_der_canonize&type=