If ever that you would try to brute force it by looking up on the wordlists for possible combinations then turn each and every possible combinations to a binary then use BIP39 algorithm to get the private key (which you can still have now or not), you would simply get 2^132 which is 5.4445179e+39
The English wordlist for BIP 39 contains 2048 words, so in order to crack a 12-word phrase it would require figuring out 2048^12 = 2^132 possible combinations under a shield of 128-bit security.
If ever that you can remember even just the mnemonics, you can simply use
https://iancoleman.io/bip39/? .
I might try doing this tomorrow just if ever I could crack it. I'll just send you a PM once I'm ready.