Post
Topic
Board Development & Technical Discussion
Re: Maths Q1 - address to key ratio
by
o_e_l_e_o
on 06/01/2021, 08:26:51 UTC
Why do you have 4 possibilities for one character? Isn't it 16? (0-F). I don't get this.
You are right that each character can be one of 16 possibilities, from 0-F, and you are right that if you know one character then then instead of it being 1664 = 2256 combinations it is 1663 = 2252 combinations.

My point was that OP had asked what would happen if the person gave you a number of different options for a character - "eg, for the fifth position is either 1, 3, f or a". In that case, instead of that position having 24 possibilities, it instead has 22 possibilities, so the total number of possibilities would reduce from 2256 to 2254. Given that, even if you only had 4 possibilities for every character in the key, you would still be left with 2128 possibilities overall, which is still impossible to even consider brute forcing.