Post
Topic
Board Gambling
Re: FreeBitco.in-$200 FreeBTC⭐Win Lambo🔥0.2BTC DailyJackpot🏆$32,500 Wager Contest
by
LoyceV
on 19/01/2021, 08:40:43 UTC
50,000 Sats is the limit for a fee of 1 Sat/byte.

I checked all addresses with less than 50,000 sat. The total balance is 18,088.92659937 BTC. That means FreeBitco.in owns 1.266% of all dust.
In total, 22,918,211 addresses hold less than 50,000 sat. Assuming an even distribution, 1.226% puts you at around 290,000 inputs. This is enough to fill about 43 blocks. Assuming my estimate on the number of addresses is correct: consolidating everything at 1 sat/byte would cost 0.43 BTC, which is only 0.19% of the 229 BTC value.
I'll have to check with wetsuit but I think the even distribution isn't that even. He said the cost would be greater than 5%.
Edit:
wetsuit just clarified it. The 5% number was completely wrong, most likely a memory lapse on my part.
My numbers were wrong too: I completely forgot the possibility of an address having multiple inputs, and I only looked at the total balance per address. The total number of small inputs is likely to be much larger.

Quote
The 229 BTC is made up of 1,382,227 UTxOs. So if 50 takes 9,850 bytes that's 197 bytes each meaning 272,298,719 bytes total or minimum cost of 2.72298719 BTC.
Thanks for the numbers. Fees are probably not enough to make a deal with a miner to include your transactions at less than 1 sat/byte when blocks have space left.