Ninjastic
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Re: Bitcoin puzzle (3,350.00 BTC's )
by
bytcoin
on 16/04/2021, 15:51:08 UTC
Quote from: maa@slm on April 06, 2021, 05:10:34 PM
Quote from: maa@slm on April 02, 2021, 09:51:33 AM
Quote from: bytcoin on March 05, 2021, 07:53:23 PM
Hello! @NotATether Great to have you here in this thread... you are very welcome. I have some interesting news from the other thread. And I also have a method that almost solved this one. And more other interesting things. I will send the link of this tool that you asked for.
The other day we will talk in private

I am newbie
how to run code with sage and python
can you provide sage and python code

off topic post below

r1: 99935505760319748698811422354322418311203851828465328908708024011195996180829
                s1: 14810718830809274529170993651437030466460552688297005873719201854608653306524
                e1: 84635513758865831094131084311208775267495704821994249663954751780286420288259
                r2: 115035229747891778996889965749694763606205313739267493174821202115705061416296
                s2: 56412229366601912356674994073152925730313351483910294670205660420888695151902
                e2: 711922952377524543467576566144169816136170490747613227449590530659320692002
              s1-1: 49589235156255394867995584868850296899036724345858375131186053009052960413985
              s2-1: 75860710922369590624024015031955497020040967297713867268831531011990818769063
            s2-1e2: 24319896032458654235859288439366790171987421552616806414321622974227628294346
            s1-1e1: 33373073398809441106621025265904429856170478887328914010434069704980389675914
            s2-1r2: 102756882304321902845902604711749179835279156262963247575454606290129811589248
            s1-1r1: 109263722787838616791900575947640359553086907200677310074463510255775504782173
1 - s2-1e2 + s1-1e1: 9053177366350786870761736826537639684183057334712107596112446730752761381569
    s2-1r2 - s1-1r1: 109285248753799481477573013772796728135029813341360841883596259175872468301412
 (s2-1r2 - s1-1r1)-1: 88597492899895469960154264896435952736065060080234931949365434864574123803941
                dU: 74071287274168731384314914382498140270634658281328726941106265589917762050271


thanks in advance...


I tried to solve the first and the second signature respectively
dU = (1 - s2-1e2 + s1-1e1) * (s2-1r2 - s1-1r1)-1 (mod n)

Any one can help me please.....
The calculations are much more difficult than I imagined ... To try to solve this you need to have a very advanced knowledge of linear equations.
The only clue is that the nonce k of the second forged signature is half of the first signature. What remains for us is to try to find some method to explore this information. ANY INFORMATION on the private key or nonce is very valuable. I'll give you an example ... If anyone knows if the private key is even or odd or if the public key is from a private key above 57896044618658097711785492504343953926418782139537452191302581570759080747168, it is possible to factor ... and in approximately 10 minutes discover any private key.