Post
Topic
Board Development & Technical Discussion
Re: Pollard's kangaroo ECDLP solver
by
NotATether
on 25/04/2021, 18:30:48 UTC
I want to do a test.
Part of the oscillator
0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798, 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

I'd like to know that this is the most basic so it shouldn't be modified
For testing purposes, I want to change this public key value and run the kangaroo.

1 = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798, 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

10 = 0xa0434d9e47f3c86235477c7b1ae6ae5d3442d49b1943c2b752a68e2a47e247c7, 0x893aba425419bc27a3b6c7e693a24c696f794c2ed877a1593cbee53b037368d7
1/10 = 0.1

0.1= 0x8c6154856794fcd5ee79ba8c96b7dd980e289a6b93a52d50dbdb9388a4c75604, 0x8fa03512509c5caa2238ef16720c9b787961e695e5401a6f5df6817ad0032d5c
priv = (81054462466121336796499689506081535496986294995352433067823614199062713046036)

Is this bolded number and point corresponding to G? Because this will make the problem easier to understand. I'm not really sure what you're trying to do when you say "oscillator".

I'm assuming you took the modular inverse G*(10G)-1 to get the 0.1 result? (And not just did straight up division of the 10 by the 1 Smiley)

I don't really see the point of using G/10 as the generator point for Kangaroo but it's technically possible if you edit the jump table.