
mean that is x2
what you want is important what is correct location of x1, x2, x3
if you calc wrong, you will never reach at your target
It doesn't matter what your x1 is or x2. Someone will jump from a different point to eg. Point 2 and in this case that point will be Point 1 with (x1, y1) and someone else will jump to eg. Point 6 and in that case that point will be Point 1 with (x1, y1). But both will have as result the point
x = 0x991eb8eb2e45b4bc9c71bc9a022832e712a8dc1b2db62bd7456e49b2d9f7dac8
y = 0x14c3c6d1a538e95f34bf05f71d9e90b8ba6195e33f0d6dd7c97695e21a09ca63
as their reference point (the lowest values for x and y in the 6-Point-Group) and will go on with that point.
Thereafter they will always have the same reference point and in the case of 'tame' and 'wild' it would lead to a solution.