With last ptx optimisation (forgot about simmetry in batch point addition)
solve 16 pubkeys from JLP in 58s
Ofcourse JLP would probably have done it even faster
solve 16 pubkeys from JLP in 58s
Code:
...
GPU#0 Cnt:0000000000000000000000000000000000000000000000000000000000000001
GPU#0 Cnt:0000000000000000000000000000000000000000000000004673f00000000001 1121MKey/s x1073741824 2^30.13 x2^31=2^61.13
***********GPU#0************
KEY!!>49dccfd96dc5df56487436f5a1b18c4f5d34f65ddb48cb5e7ad38337c7f173c7
Pub: 55b95bef84a6045a505d015ef15e136e0a31cc2aa00fa4bca62e5df215ee981b3b4d6bce33718dc6cf59f28b550648d7e8b2796ac36f25ff0c01f8bc42a16fd9
****************************
Found in 4 seconds
GPU#0 job finished
Working time 00:00:58s
Total time 00:06:33s
GPU#0 thread finished
cuda finished ok
Press Enter to exit
Seems like it is the maximum that I can achieve in single 2080ti.GPU#0 Cnt:0000000000000000000000000000000000000000000000000000000000000001
GPU#0 Cnt:0000000000000000000000000000000000000000000000004673f00000000001 1121MKey/s x1073741824 2^30.13 x2^31=2^61.13
***********GPU#0************
KEY!!>49dccfd96dc5df56487436f5a1b18c4f5d34f65ddb48cb5e7ad38337c7f173c7
Pub: 55b95bef84a6045a505d015ef15e136e0a31cc2aa00fa4bca62e5df215ee981b3b4d6bce33718dc6cf59f28b550648d7e8b2796ac36f25ff0c01f8bc42a16fd9
****************************
Found in 4 seconds
GPU#0 job finished
Working time 00:00:58s
Total time 00:06:33s
GPU#0 thread finished
cuda finished ok
Press Enter to exit
Ofcourse JLP would probably have done it even faster
impressive Etar . i have question . lets say if you have 1m keys in file and you load in bsgscuda and set scan range only to 64, now my question is if gpu finished whole 64 range scan for key1 than gpu will abandoned search of key1 and move to key2?
your program is doing that or you will impalement this. right?