Post
Topic
Board Bitcoin Discussion
Re: Craig Wright? - signed Bitcoin message
by
iamonlinenow
on 30/10/2021, 16:27:52 UTC
So we can say, that if you can sign with (1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W) then you have the private key of Satoshi's key.
Yeah. If you knew the private key of - 1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W - you'd be one step far from calculating this sought after Satoshi's address. It's simple elliptic curve maths.

If k1G + k2G = k3G then (k1 + k2)G = k3G  →   k1 + k2 = k3.

Beautiful, isn't it?
... the idea is the same, you keep going backwards (t > h > g > i > r > W > C)...

That means the creator can't sign with the 'r' key, similar to the 1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W case.

The creator starts with the signature address
17mZRodKy5ufNqJVsyKg1bEt81AnRkkh9L

then calculates the pubkeys for  (t > h > g > i > r > W > C)
but for 'r' =
1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG
the creator doesn't have the private key but can show the public key and the address.

To prove the ownership of satoshi"s private key we would need 2 signatures:
1. for 17mZRodKy5ufNqJVsyKg1bEt81AnRkkh9L (it is posted)
2. for 1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG (not posted)

To the creator:
Post a signature for 1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG