Re: Pollard's kangaroo ECDLP solver

https://github.com/ragestack/EC-Point-Operations/blob/master/EC_Math.py
https://bitcointalk.org/index.php?topic=5244940.msg58488513#msg58488513

Code:

Point1 = (x1,y1)
Point2 = (x2,y2)

Point3 = sub(Point1,Point2)
Point4 = add(Point1,Point2)
Point5 = div(Point1,2) # remove Scalar option, i need two point use div Point5 = div(Point1,Point2)
Point6 = mul(Point1,2) # remove Scalar option, i need two point use mul Point6 = mul(Point1,Point2)

i need two point use div Point5 = div(Point1,Point2) #remove Scalar option
i need two point use mul Point6 = mul(Point1,Point2) # remove Scalar option
eny method Point1,Point2 use div and mul get therd point #mybadenglish
read my top 2 link modify please..

its posible remove scalar

Code:

#modify please
def ECdiv(Qx,Qy,Scalar): # EC point division remove Scalar option
   A = (N-1)/Scalar
   Px,Py = ECmul(Qx,Qy,A)
   Py = P-Py
   return Px,Py
Dx,Dy = ECdiv(Cx,Cy,2)
print (Dx,Dy)

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