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Topic
Board Bitcoin Discussion
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
enfarktus
on 15/01/2022, 15:31:16 UTC



Hi all this easy matematic 1+1 code
code:
from bit import Key
import random
for x in range(1000000000):
 xx = random.randint(4611686018427387904,9223372036854775808)
 cc = xx+xx
 k1 = Key.from_int(int(cc))
 if (str(k1)).startswith("<PrivateKey: 16jY"):
  print(cc,xx,k1,x)
 if (str(k1)) == "<PrivateKey: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN>":
  f=open("win.txt","a")
  f.write(str(cc)+(str(k1))+"\n")
  f.close()
the simpler the faster
code compute 4611686018427387904 to 9223372036854775808 take one number maximum 9223372036854775808 keyspace and doubles it him final decimal is private key little reduces the key space

Nice work. Thank  you for share.