Post
Topic
Board Project Development
Re: Keyhunt - development requests - bug reports
by
PrivatePerson
on 09/03/2022, 07:49:11 UTC
My idea is precalculate this part: **7ae41e4649b934c****991b7852b855 and just brute force the second.
if all the missing characters were together then it can be solved with BSGS in seconds

Can you explain (maybe there are ready-made solutions):
1. How to split the private key into parts and brute through it in parts?
2. How to brute a private key with missing characters together?