Post
Topic
Board Development & Technical Discussion
Re: Pollard's kangaroo ECDLP solver
by
dextronomous
on 25/03/2022, 23:56:57 UTC
I found a method to find any private key within 2^255 bit space. Is that new?

Tell us if you've already decided to brag  Wink

Upd. Better yet, just prove it. I generated a random key. Here is the public key for it
0337aff652dd11e2870636b0c4ce4fb324f4b0df45e70f7d8c77d15fcc9ae73525

I would have to know the key for 0237aff652dd11e2870636b0c4ce4fb324f4b0df45e70f7d8c77d15fcc9ae73525 as it would we below ~2^255 if 0337aff652dd11e2870636b0c4ce4fb324f4b0df45e70f7d8c77d15fcc9ae73525 is above.
hi Boris,
line 92, in validate_secret
    raise ValueError('Secret scalar must be greater than 0 and less than {}.'.format(GROUP_ORDER_INT))
ValueError: Secret scalar must be greater than 0 and less than 115792089237316195423570985008687907852837564279074904382605163141518161494337.
you might know why, what should i do here?