So, you're saying to put a 120k resistor across C32 in parallel with it, right?
If one chooses the single resistor method of 54.54k instead, it is to replace R52 instead, right?
No longer any need for the 4 previous mods i.e. 2 jumpers, 39k and pencil mod, correct?
The ultimate option / mod is:
Just a single resistor (54.54k) solution and that's it?
If so,,,,
How sweet it is!
Wolfey2014
If one chooses the single resistor method of 54.54k instead, it is to replace R52 instead, right?
No longer any need for the 4 previous mods i.e. 2 jumpers, 39k and pencil mod, correct?
The ultimate option / mod is:
Just a single resistor (54.54k) solution and that's it?
If so,,,,
How sweet it is!
Wolfey2014
Exactly.
There are an equalation for cmos logic IC power consumption:
P=c*f*V^2+Pleakage, where c is a constant.
Gridseed uses 45nm technology, so Pleakage is high, but you see P~V^2.
If you divide it with the nominal values, you will get P/Pn=1200/850*2^2/1.2^2 -> P=4*Pn plus the leakage, but it is not easy to calculate.
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