in my tests, 0780 & 4f81 yielded the same result - so I think they are both very close, if not 400mhz
I can confirm that my overnight test seems to be a success... averaging 197GH @ .59% HW ... which is higher than the 375mhz setting, but lower than 400mhz
I dont know what the exact equation is for figuring out hashrate based on clock but the numbers match up with 512*mhz = mh/s
Based on that equation, 5e82 seems to clock in right around 384mhz
Also, if someone wants to experiment w/ the xx83 ranges ... I imagine the values will start in the 6x83...
I can confirm that my overnight test seems to be a success... averaging 197GH @ .59% HW ... which is higher than the 375mhz setting, but lower than 400mhz
I dont know what the exact equation is for figuring out hashrate based on clock but the numbers match up with 512*mhz = mh/s
Based on that equation, 5e82 seems to clock in right around 384mhz
Also, if someone wants to experiment w/ the xx83 ranges ... I imagine the values will start in the 6x83...
I now figure out the HEX.
400MHz = 0780, = 4F81 and also = 5F82, but 0780 and 4F81 are preferable,
as it comes with the config and don't know whether 5F82 will do any harm.
387.5 MHz = 4F01 and also = 5E82, you may try 4F01, it should be OK (may give different HW error, but same MHz)
So I tried something like 412.5 MHz '5001', and again very high HW errors 4.x% (~ 425MHz's HW error).
I think I have good-enough cooling, it might be the hardware stuff for the error, so I went back to 400MHz then.
Did u just figure out those particular ones or do you know what the actual "pattern/equation" is?
Here they are ...
It comes from the Antminer U1 overclock manual. But I think this should be compatible to Antminer S1, too.
Let's see the example of why 0780 and 4F81 are 400MHz.
HEX BINARY 15/BS M N OD
0780 0000 0111 1000 0000 00 00 0111 1 = 15 000 00 = 0 00 = 0 which NO=1
4F81 0100 1111 1000 0001 01 00 1111 1 = 31 000 00 = 0 01 = 1 which NO=2
5F82 0101 1111 1000 0010 01 01 1111 1 = 63 000 00 = 0 10 = 2 which NO=4
Fout = 25 * (M+1) / ((N+1)*NO)
Fout(0780) = 25 * (15+1) / (1*1) = (25*16)/1 = 400 MHz
Fout(4F81) = 25 * (31+1) / (1*2) = (25*32)/2 = 400 MHz
Fout(5F82) = 25 * (63+1) / (1*4) = (25*64)/4 = 400 MHz
Actually, 5F82 is also 400 MHz, but due to the instruction below 500 <= Fout * NO <=1000
Fout(5F82) = 400MHz, therefore, Fout*4 = 1600 and over 1000.
So I think I should not config 5F82 for 400MHz, according to this manual.
I don't say that it does not work (I tried it before understanding the HEX, it worked)
but you have also another 2 freq_values which give you the same MHz and get along with the instruction in the manual.
A little bit too long, anyway, I hope you enjoy my lecture, lol.
Any questions are welcome.
If this is useful, any donations/tips are welcome => 12QAQhbmTzV7sJ9sg8xT96JAneE4S89sS6
Sorry to pull up and old post.
could somebody help how can i figure out M and N?
I understand everything except this.
Thanks