Post
Topic
Board Bitcoin Discussion
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
BTC_Backdoor
on 31/05/2023, 06:09:54 UTC

Can you tell me why is this happening? Ok, if I subtract this

Code:
02A1940074961CDF60CB2A0E7BC7157A7970B05469C58EEB5AD1C0462CE0C17811
from #125 puzzle, the result is :

Code:
02ed01ff219ed5c1afc12d991a82e3063ddcee1fd53b46f7cad52a0d87a7112aed

And if I subtract this
Code:
0290ad85b389d6b936463f9d0512678de208cc330b11307fffab7ac63e3fb04ed4
which is actually 2^124 public key, if I subtract it from #125 puzzle the result is :
Code:
03ed01ff219ed5c1afc12d991a82e3063ddcee1fd53b46f7cad52a0d87a7112aed

I know why this is happening though, because the first subtraction is actually inverse addition, the distance between the first public key and the second one is exactly the private key of #125.

This is why I'm stuck and can't solve this puzzle, and this is one of the easiest of puzzles since we know exactly it starts with a 1.
But I am close God willing, it should be solved soon.


Ohh boy you are 100% correct. The real problem is one can only do first subtraction and after all, it doesn't reduces its size. Why? let me explain.
The private key which we are looking for is between 2^124 : 2^125.
Now you need to understand that amount of numbers or p.keys from 1 to 2^124 is equal to the amount between 2^124 : 2^125.
So when we subtract 2^124 from the pubkey which is between 2^124 : 2^125, then we are actually making it fall between the range of 1 to 2^124.
Let me take you to a step further. If the puzzle private key is above the half in range 2^124 : 2^125, then you can do one more subtraction. You can further subtract 2^123 from previous subtraction result. That's it.
So far, I figured that to actually work with this subtraction thing, one need a data base of public key from 2 to 2 Trillion for that matter or more, and perform various models of subtraction from puzzle pub key and check if resulting pubkey is falling within that 2 to 2 trillion result. That's the best shot I've reached so far.