Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
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I guess you are way off the map! 2 trillion keys? The actual number is 5 to 6 public keys in order to form 2 triangles and solve the key, more than that will confuse you, as it has confused me with a few million keys, I see hexadecimal characters wherever I look, after working on them for hours. Lol.
LOL, these hexadecimals do often come into my dreams and dancing around as well.
I sure didn't got your point of TRIANGLES. What I was referring to trillion thing is this.. Suppose we are searching the private key which is within bit range of 16:32. I made a list of initial 6 public keys like I have a file in which 1-6 public keys are stored. Now I subtract 16 from the puzzle public key. Suppose the hidden private key is 21. So when I subtract 16 from it the resulting key at the same position but in lower bit size. Now 21-16=5 and now I check whether this public key is in my file in which I saved initial public keys. So this is simple thing I am referring as 2 trillions... Can you explain your TRIANGLE THING?
??About triangulation, it is similar to how GPS works, but instead of sending and receiving signals, we add and subtract, you basically need only to know the value of 2 keys out of 6 keys, you have to find mutually related keys and find your way by adding and subtracting your 2 known keys to and from 4 unknown mutually related keys to find one of them!
It is rather complex, if I had the whole idea pictured in front of me, I could have explained it better, this however is easy to do on #125 because we know the first character is 1, and if I manage to solve it, the method won't work for any other puzzle, unless another puzzle starts with 1. Lol.
I'm going to call this method, "PPP" short for PinPointing
Position!
I have managed to figure out that #125 starts with obviously 1 and the second character is definitely greater than 4, but I know for sure it is greater than 14000000000000000000000000000000 I'm still confused about the way numbers work in EC, but if for example I use 2^124 aka 10000000000000000000000000000000 as one of my 2 base point keys, I just need to add and subtract other secret keys by the same numbers to see if I can find a few of their mutual friends, that is how I'd know which one is smaller than my target.
But now I could be subtracting a -n key from my target and actually be adding their difference to my target, e.g subtracting -70 from +50 will result in +70, f@ck I just realized something after typing this. Lol.