Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
⭐ Merited by digaran (1)
Anyone here knows how to divide a point by 3, 4, 5, 6, 7, 8, 9 and 10 and get a correct result?
Give me a few minutes, you will be amazed, I need to prepare the sample keys on laptop. Stay tuned.😉
Give me a few minutes, you will be amazed, I need to prepare the sample keys on laptop. Stay tuned.😉
Look forward to explanations! Good luck bro!
5- another form of successive subtraction
Code:
import secp256k1 as ice
target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub).hex()
print(res)
target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub).hex()
print(res)
Tell me how to make each pub write from a new line, and not all in one line?
Code:
import secp256k1 as ice
target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub)
for t in range (num+1):
h= res[t*65:t*65+65]
data = open("loop-subtrac.txt","a")
data.write(str(h.hex())+"\n")
data.close()
target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub)
for t in range (num+1):
h= res[t*65:t*65+65]
data = open("loop-subtrac.txt","a")
data.write(str(h.hex())+"\n")
data.close()