its not blind searching
03982a5a42895a5cfe4b9b98e49f9389ebf9b3bf91c2289f1c5db3d944f46ec710
hash160
3aaccf438388c4aeb0b433c7b778f25cb6ab244c
hash160
3aaccf438388c31f14410f489939d3d5eac88f19
pk: 48ea48b7a25627365cff38d
13 same hash160 digits, and its two substraction of 130 its not one substraction, 13 digits means its 80 pourcent in that range like puzzle 66
03982a5a42895a5cfe4b9b98e49f9389ebf9b3bf91c2289f1c5db3d944f46ec710 + 2786b52d106d22524ed9cf8a87d2
031ed6283a43d439eace1ee2815118cb6f16f475be60fa5ccc8598372d8c5f1995 # target
031ed6283a43d439eace1ee2815118cb6f16f475be60fa5ccc8598372d8c5f1995 # + 3.........................................
03633cbe3ec02b9401c5effa144c5b4d22f87940259634858fc7e59b1c09937852 # target
Can you show one example where you could find a key based on rmd160 similarities? I'd like to learn this non existing equation where we can estimate EC points range by finding rmd160 similar starting characters.
I have this rmd160 as my address
000000009f012a539f3df386f0bddbb874af55ec
I should get to work and find this address 1111111111111111111114oLvT2
With rmd160 of
0000000000000000000000000000000000000000 ? Lol I'm done.